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Former Member
Posts: 1,876,323 The Mix Honorary Guru
in General Chat
Sally bear and her 5 sisters are having a picnic. Sally brought her boyfriend and he brought 32 mates. Sally's sisters brought 12 mates each and when they got there. they met half as many bears again. Big picnic.
Count all the bears
Someone please solve this for me :crying:
Count all the bears
Someone please solve this for me :crying:
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Ok this answer is wrong, I forgot to add Sally and her sisters to the total. My answer down there is correct! (ish)
l
l
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but also....how can you have half a bear????
S + (Boyfriend + 32) = 34
5 sisters + (12mates x 5) = 75 which added to Sally's lot = 109 (oh hang on this is different to what I worked out just now!) erm bear with me (hehe)
then 109/2 = 54.5
So 109 bears + 54.5 bears = 163.5 bears
Ok I change my answer!
sisters - 5 = 6
boyfriend- 1 = 7
bf mates - 32 = 39
sister * 12 - 60 = 99
This part confuses me. :chin:
When they all got together, they met half the amount of bears - right? 99 is an odd number and can't be divided by 2 to form a whole number. If you like chopping bears up, then you would get 99 + 49.5 = 148.5 bears . Since you can't have half a bear, and you can't round up, the answer should be 148 bears.
Anybody tell me what I've done wrong?
So did I.
Do you really know if her boyfriend is a bear or not?
EDITED: Mates can be bears too can't they?
They met half the bears again. It should be nine bears.
Sally + boyfriend and 32 mates = 34
5 sisters + (12 mates x 5) =60 (not 70!!!)
60+34 = 94
94/2 = 47
94+47 = 141 bears.
as was 1, 2, 130, 148, 149, 148.5 and i shall add more as i remember them
but you didn't count the 5 sisters!
I give up. Unless Sally bear is the only bear because she was adopted into a non-bear household?
For example in this one you might have to consider not only the bears in the question, but the number of times the word "bear" appears in the question as well.
Only one "bears"
You haven't added on the sisters here, you just counted the friends.
I reckon moonarcanum is right - there is some sort of trick here that we aren't seeing ...