Math - trigonometri

Former Member · May 2004

Zalbor, I asked for help and not for a lecture.
I am pretty decent at math, and my grade isn't bad. But being that I was sick for the most of last year, and spent more time with doctors than class, and when I was in class I was on strong medication which made it hard to concentrate, I lack some basics which we went through then - and that I tried to catch up on before my test today.

My test today went okay, and now I can only wait for my grade. Succeeded to answer everything, and to find (hopefully correct) solutions.

So while I thank you for your time and help attempted, I am not fond of your criticism, as I seriously don't think that it's deserved.

Indrid Cold · May 2004

Originally posted by Jacqueline the Ripper
Zalbor, I asked for help and not for a lecture.
...But being that I was sick for the most of last year...
I am not fond of your criticism, as I seriously don't think that it's deserved.

I'm sorry, I didn't know that. I thought you were only being lazy (as I was for much of the time). The "lecture" wasn't intended to be cririsism, only advice to avoid problems that I almost had.
It's good to know that it went well after all, and I wish you success. I hope you're over the sickness too, and be well from now on.

Former Member · May 2004

Thank you

Former Member · May 2004

Originally posted by Randomgirl
Seeing as you know only one angle but two lengths you need to use the "cosine rule".

Cos A = (b squared + c squared - a squared) / 2bc

the cosine rule is: a squared = b squared + c squared -2bc cos A

A being the angle a being the opposite side.
you can rearrange the letters to fit your thingy without changing the formula

you're diagram is kinda unclear though and i couldnt be bothered to read what everyone else wrote

Math - trigonometri

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